(6分之x-1)-(3分之x+2)=(2分之x-1)=+1怎么解

2025-06-23 06:30:13
推荐回答(2个)
回答1:

(x-1)/6-(x+2)/3=(x-1)/2+1
x-1-2(x+2)=3(x-1)+6
x-1-2x-4=3x-3+6
3x+1=-5-3
4x=-8
x=-2

回答2:

(6分之x-1)-(3分之x+2)=(2分之x-1)+1
x-1-2(x+2)=3(x-1)+6
x-1-2x-4=3x-3+6
4x=-8
x=-2