(1)BA=10-8=2四边形OCDB是平行四边形,CD=OB=OA-BA=10-2=8,FM²=MD²-FD²=(AB/2)²-(CD/2)=5²-4²CD的弦心距=FM=3;(2)作CH⊥AB,垂足H,OM=AB/2=10/25,HM=CE=CD/2=8/2=4OH=OM-HM=5-4=1;C纵坐标数值=CD的弦心距=3,所以C(1,3);D纵坐标数值=CD的弦心距=3,横坐标=OH+CD=1+8=9,所以D(9,3).