曲线y=h(x)在点(0,,h(0))处的切线方程为y=h'(0)x+h(0)=x+1因此有h'(0)=1,h(0)=1曲线f(x)=h(x)+2xf'(x)=h'(x)+2f(0)=h(0),f'(0)=h'(0)+2在点(0,,f(0))处的切线方程为y=(h'(0)+2)x+h(0)=3x+1选a
