解(-3又3⼀8)负的2⼀3次方+(0.002)负的1⼀2次方

2025-06-23 00:23:27
推荐回答(1个)
回答1:

(-3又8分之3)^﹣2/3+(0.002)﹣½-10(√5-2)﹣¹+(√2-√3)º
=(-27/8)^﹣2/3+(1/0.002)½-10×1/(√5-2)+1
=(-8/27)^2/3+√500-10(√5+2)/[(√5-2)(√5+2)]+1
=4/9+10√5-10√5-20+1
=-18又9分之5