∵∠FOC=90°，∠1=40°，AB为直线，∴∠3+∠FOC+∠1=180°，∴∠3=180°-90°-40°=50°．∠3与∠AOD互补，∴∠AOD=180°-∠3=130°，∵OE平分∠AOD，∴∠2= 1 2 ∠AOD=65°．
