lim(sin(x-1))⼀(x^2+x-2),x趋于1,求极限

2025-06-20 15:49:32
推荐回答(1个)
回答1:

令a=x-1
则a趋于0
x²+x-2=(x-1)(x+2)=a(a+3)
所以原式=lim(a→0)sina/a(a+3)
=lim(a→0)sina/a*lim(a→0)1/(a+3)
=1*1/(0+3)
=1/3