设2p+1=qn,2q-3=pm(n,m≥1,q,p为奇质数)=>3(2p+1)+2q-3=3qn+pm=>3qn+pm=6p+2q(3n-2)q=p(6-m)因2p+1=qn,则p≠q则3n-2=p,6-m=q≥3则m=1,q=5,可得p=7m=3,得出q=3,无对应的p值则q=5,p=7
自己想吧
