电路如图所示,已知US=20V,IS=10A,R1=6,R2=4,R3=4,R4=6,用戴维宁定理求R4上的电压U

2025-06-23 08:35:58
推荐回答(1个)
回答1:

按规则断开 R1 ,求 Uab :

Uab = Us + Is * R2 = 20 + 10 * 4 = 60 V

Us 短路、Is 开路,求 Rab :

Rab = R2 = 4 Ω


IR4 = Uab / (Rab + R4) = 6 A

U = IR4 * R4 = 36 V