在等差数列中,a1=12,an=24,sn=90,求公差d和相数n

2025-06-23 09:27:50
推荐回答(1个)
回答1:

Sn=[n(a1+an)]/2
[n(12+24)]/2=90
n=5
即:a1=12,a5=24
则:a5=a1+12d
24=12+12d
d=1