求解:limx→1,x^2+5⼀x limx→2,(2x+1) limx→∞,3x^3-x-7⼀1+5x^2+3x^3 (sinx)^1 (lnx+e^-x)^1 d(x^2)

2025-06-22 19:12:28
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回答1:

imx→1,x^2+5/x,极限为(x^2+5)/x=6
limx→2,(2x+1) ,极限为5
limx→∞,3x^3-x-7/1+5x^2+3x^3 (sinx)^1 (lnx+e^-x)^1 d(x^2),不知表达啥意思?看不懂