、用规格相同的滑轮安装成甲、乙两个滑轮组提升重物,如图所示,已知G1=150N,G2=200N,动滑轮重G动=50N,

2025-06-20 09:06:37
推荐回答(1个)
回答1:

A、F1(1)、F1=G总/3=(50N+150N)/3=66.7N
F2=G总/2=(50N+200N)/2=125N
所以F1(2)、η1=(Gh)/(FS)=(Gh)/(Fx 3h)=G/(3F)=150/(3x66.7)=75%
η1=(Gh)/(FS)=(Gh)/(Fx 2h)=G/(2F)=200/(2x125)=80%