积分; 如下图,∫ arctanxdx怎么求

2025-06-22 08:20:34
推荐回答(1个)
回答1:

用分部积分法
∫arctanxdx = xarctanx - ∫xdarctanx
= xarctanx - ∫[x/(1+x^2)]dx = xarctanx - (1/2)∫[d(1+x^2)/(1+x^2)]
= xarctanx - (1/2)ln(1+x^2) + C2