原式=3A-3B-2A-B=A-4B=(4x²-4xy+y²)-4(x²+xy-5y²)=4x²-4xy+y²-4x²-4xy+20y²=-8xy+21y²
已知A=4x²-4xy+y², B=X²+XY-5Y², 求(3A-3B)-(2A+B)解: (3A-3B)-(2A+B)=A-4B=(4x²-4xy+y²)-4(X²+XY-5Y²)=-8xy+21y²=
-20xy+21y²
21y2 -8xy