计算行列式，第一题的2还有第二题

2025-06-20 08:30:22

推荐回答（1个）

回答1：

A =
1 2 3 4
2 3 4 1
3 4 1 2
4 1 2 3

=
10 2 3 4
10 3 4 1
10 4 1 2
10 1 2 3

=
10 2 3 4
0 1 1 -3
0 2 -2 -2
0 -1 -1 -1

=
10 2 3 4
0 1 1 -3
0 0 -4 4
0 0 0 -4

= 160

D =
1 -5 3 -3
-5 1 3 -4
2 0 1 -1
3 1 -1 2

=
1 -5 3 -3
0 -24 18 -19
0 10 -5 5
0 16 -10 11

=
1 -5 3 -3
0 -4 8 -9
0 10 -5 5
0 16 -10 11

=
1 -5 3 -3
0 -4 8 -9
0 2 11 -13
0 0 22 -25

=
1 -5 3 -3
0 0 30 -35
0 2 11 -13
0 0 22 -25

=
1 -5 3 -3
0 0 8 -10
0 2 11 -13
0 0 22 -25

=
1 -5 3 -3
0 0 8 -10
0 2 11 -13
0 0 -2 5

=
1 -5 3 -3
0 0 0 10
0 2 11 -13
0 0 -2 5

= 40