额，基本求导法则里都有，你想知道什么-sin(x^(1/2))/(2·x^(1/2))-ln2·(2^x)
y=cos√x+2＾xy'=-sin√x/(2√x)+ln2*2＾xdy=[-sin√x/(2√x)+ln2*2＾x]dx
