高数,这道题怎么求,求过程

2025-06-21 09:58:16
推荐回答(1个)
回答1:

隔项级数,则收敛半径的平方是
R^2 = lim|a/a|
= lim|n^2[2^(n+1)+(-3)^(n+1)]/{(n+1)^2[2^n+(-3)^n]}|
= limn^2/(n+1)^2 lim|[2^(n+1)+(-3)^(n+1)]/[2^n+(-3)^n]|
= 1· lim|[2(2/3)^n+(-3)(-1)^n]/[(2/3)^n+(-1)^n]| = 3
R = √3