求十道有理数加减乘除运算题，最好四个数。拜托各位老大了

0.7×19又5/9+2又3/4×（-14）+7/10×4/9-3.25×14
=0.7×（19又5/9+4/9）-（2又3/4+3.25）×14
=0.7×20-6×14
=14-84
=-70

0.25*(-2)三次方-[4/(-2/3)二次方]+(-1)两千一十三次方
=0.25*(-8)-[4/(4/9)]-1
=-2-9-1
=-12

(–1/30)÷(7/9-5/6+3/4+7/2)
=–1÷(7/9×30-5/6×30+3/4×30+7/2×30)
=-1÷（28-30+22.5+105）
=-1÷120.5
=-2/241

-40-28-（-19）+（-24)-(-32)
=-68+19-24+32
=-49-24+32
=-73-32
=-41

-36×（-7/9）+（-36）×5/6-（-36）×3/4
=36×（7/9-5/6+3/4）
=36×29/36
=29

(一0.15一7/5十5/12一2又1/4）÷（-1/60）
=(一0.15一7/5十5/12一2又1/4）×（-60）
=0.15×60+7/5×60-5/12×60+2又1/4×60
=9+72-25+135
=191

-1又1/3×（-3又3/4）×（-2007）×（-0.5）+1/2
=4/3×15/4×2007×0.5+1/2
=5×0.5×2007+1/2
=2.5×2007+1/2
=5017.5+1/2
=5018

（4/7×1/9×4/11）÷（2/11×2/7×5/9）
=（4/7÷2/7）×（1/9÷5/9）×（4/11÷2/11）
=2×1/5×2
=4/5
[2又2分之1一(9分之7一12分之11+6分之1)x36]÷5
=[2又2分之1一(9分之7×36一12分之11×36+6分之1x36）]÷5
=[2又2分之1一(28-33+6）]÷5
=[2又2分之1一1]÷5
=1.5÷5
=0.3

(1/4)²÷ (-1/2)+(111/4+22/3-133/4)x24—1/8000
=1/16÷（-1/2）+（111/4×24+22/3×24-133/4×24）-1/8000
=-1/8+（666+176-798）-1/8000
=-1/8+44-1/8000
=44-1001/8000
=43又6999/8000

(8分之1-12分之5)x24-(-3-3)的2次方+(-6-3)的2次方
=1/8×24-5/12×24-6的2次方+9的2次方
=3-10-36+81
=38

21-(-7)/2/1*2
=21+14*2
=21+28
=49

1.2*(-15)-(2.4)/(-1.2)
=-18+2
=-16