解(1)由f(x)=sin(π/3-2x)=-sin(2x-π/3)当2kπ-π/2≤2x-π/3≤2kπ+π/2,k属于Z时,y是减函数,即kπ-π/12≤x≤kπ+5π/12,k属于Z时,y是减函数,知函数的减区间为[kπ-π/12,kπ+5π/12],k属于Z.