设{a n }的公差为d,,{b n }的公比为q, ∵a 1 =3,b 1 =1,a 2 =b 2 ,3a 5 =b 3 , ∴a 2 =3+d=q=b 2 , 3a 5 =3(3+4d)=q 2 =b 3 , 解方程得q=3,或q=9, 当q=3时,d=0,不符合题意,故舍去; 当q=9时,d=6. a n =3+(n-1)×6=6n-3,b n =q n-1 =9 n-1 . ∵a n =3log u b n +v= log u ( 9 3n-3 ) +v, ∴6n-3-v= log u ( 9 3n-3 ) , 当n=1时,3-v=log u 1=0, ∴v=3. 当n=2时,12-3-3= log u 9 3 , u 6 =9 3 ,u=3, ∴u+v=6. 故答案为:6. |