已知数列{a n }的各项均为正数,其前n项和为S n ,且满足2S n =a n 2 +a n (n∈N * ).(Ⅰ)求a 1 ,
2025-06-20 09:36:00
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(Ⅰ)a 1 =1,a 2 =2,a 3 =3.(3分) (Ⅱ)2S n =a n 2 +a n ,①2S n-1 =a n-1 2 +a n-1 ,(n≥2)②(5分) ①-②即得(a n -a n-1 -1)(a n +a n-1 )=0,(6分) 因为a n +a n-1 ≠0,所以a n -a n-1 =1,所以a n =n(n∈N * )(8分) (Ⅲ)(Ⅲ)∵ b n =n(