1＋√3 i＝2[cos(π/3)＋i sin(π/3)]＝2e^( πi/3 )因此原式＝ 2^17 e^( 17πi/3 )＝ 2^17 [cos(17π/3)＋i sin(17π/3)]＝2^16 * (1－√3 i)
