(1)根据酸度的表示方法,酸度(AG)AG=lg
.中性溶液中C(H+)=C(OH-),AG=lgc(H+) c(OH?)
=0;常温下0.01mol?L-1盐酸溶液中,C(H+)?C(OH-)=10-14,溶液中C(H∪)=10-2mol/Lc(H+) c(OH?)
C(OH-)=
=10-12mol/L,所以溶液的酸度AG=lg10?14
10?2
=lgc(H+) c(OH?)
=lg1010=10;10?2mol/L 10?12mol/L
故答案为:0 10
(2)①FeO(s)+CO(g)=Fe(s)+CO2(g)△H=-218kJ/mol
②Fe3O4(s)+CO(g)═3FeO(s)+CO2(g)△H=+640.5kJ/mol
根据盖斯定律,①×3+②得到:Fe3O4(s)+4CO(g)═3Fe(s)+4CO2(g)△H=-13.5KJ/mol;
故答案为:Fe3O4(s)+4CO(g)═3Fe(s)+4CO2(g)△H=-13.5KJ/mol;