对称变换的性质

求证明过程,谢谢俶
2025-06-22 07:53:12
推荐回答(1个)
回答1:

(sinx)^4 = (sinx^2)^2 = ((1 - cos2x)/2)^2 = (1 - 2cos2x + (cos2x)^2)/4 = 0.25 - 0.5cos2x + 0.125(1 + cos4x) = (cos4x)/8 - (cos2x)/2 + 3/8 ∫ (sinx)^4dx = ∫ ((cos4x)/8 - (cos2x)/2 + 3/8)dx = ∫ ((cos4x)/8)dx - ∫ ((cos2x)/2)dx + ∫ (3/8)dx = (1/32)∫ cos4xd4x - (1/4)∫ cos2xd2x + (3x/8) = (sin4x)/32 - (sin2x)/4 + (3x/8) + C