已知函数f(x)=a^x(a>0,且a≠1)当x<0时,f(x)>1,方程y=ax+1⼀a表现的直线是

求详细过程和图!!!急!
2025-06-22 22:09:25
推荐回答(1个)
回答1:

log(1/24) = -log24
f(log(1/24)) = f(-log24) = -f(log24) = -a^log24 = -3
log24*loga = log3
loga = log3/log24
a = 2.2166
是否可以解决您的问题?