(1)a3+2是a2和a4的等差中项,且a1=2,∴2(a3+2)=a2+a4即2(a1q2+2)=a1q+a1q3∴q=2∴an=a1qn-1=2n(2)∵bn=2nlog22n=n?2n∴Tn=b1+b2+…+bn=1?21+2?22+3?23+…+n?2n∴2Tn=1?22+2?23+…+(n-1)?2n+n?2n+1∴-Tn=2+22+23+…+2n-n?2n+1∴Tn=(n-1)?2n+1+2