用换元法计算定积分∫【1⼀∏到2⼀∏】[1⼀(x^2)]·[sin(1⼀x)]dx?

2025-06-22 19:25:06
推荐回答(1个)
回答1:

∫(1/X²)*sin(1/X)dX
=∫-sin(1/X)d(1/X)
=cos(1/X)+C
=0-(-1)
=1